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N: 必胜局面 P: 必败局面 巴什博奕 一堆物品有 n 个,两个人轮流拿,每次至少拿 1 个,至多拿 k 个。 则n%(k+1)==0时先手必败其他情况下先手必胜 尼姆博奕 n 堆物品,第 i 堆数量为a[i],两人轮流从某一堆里曲任意多的物品 记k=a[1]^a[2]^.…
博弈论
2 min
6 years ago
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